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I've been asked to find the matrix that reflects points across the line y = 2x.
I can get the answer by considering it as a rotation of
, but this is ugly.How should it be done?
Thanks.
Last edited by Daniel123 (2008-09-21 05:08:27)
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Also, what exactly does "a shear of 30° in the direction of Oy" mean?
EDIT: Nevermind about this question - lines parallel to Ox are tilted 30° and stretched to maintain height. So the shear would be written:
Last edited by Daniel123 (2008-09-21 05:43:22)
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Reflections are not rotations.
A shear of factor k in the y-axis increases the vertical height of a point by an amount depending on k and its distance from the y-axis; horizontal distances are unaffected. Precisely, this is multiplication by the matrix
Last edited by JaneFairfax (2008-09-21 05:48:37)
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Reflections are not rotations.
I know they're not, but isn't a relfection across y = 2x equivalent to the rotation I mentioned above?
How should the question be done?
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I know they're not, but isn't a relfection across y = 2x equivalent to the rotation I mentioned above?
NO!! The matrix representing any rotation always has determinant +1 while that representing any reflection always has determinant −1. They cant possibly be equal.
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Daniel123 wrote:I know they're not, but isn't a relfection across y = 2x equivalent to the rotation I mentioned above?
NO!! The matrix representing any rotation always has determinant +1 while that representing any reflection always has determinant −1. They cant possibly be equal.
Haven't come across determinants yet
I'll try and find the proper way of doing it.
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Isn't the following treating a reflection across a line to be a rotation through twice the angle between the line and the x-axis? Is there anything wrong with it?
The X coordinate of P' is given by:
, and the Y coordinate of P' is given by . The same method can be applied to the j vector, giving the transformation matrix as:In the case where y=2x,
, which can be used along with the double angle trig identities to give the transformation matrix: , which I know is correct.When I first did this in the case y=2x, I didn't do it generally but instead calculated the angle, which is why I said it was ugly. Now that I've done it generally, I can't see anything wrong with treating a reflection as a rotation.
Last edited by Daniel123 (2008-09-21 06:43:42)
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All right, I just worked it out geometrically. A reflection about the line
would take the point to the point .Hence the matrix representing this reflection is
EDIT: Well, I see that youve managed to work it out as well.
Last edited by JaneFairfax (2008-09-21 06:44:39)
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All right, I just worked it out geometrically. A reflection about the line
would take the point to the point .Hence the matrix representing this reflection is
Beat you ever so slightly
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