Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2008-10-18 01:44:01

DAN7891
Guest

Cubic Logarithms

Can anyone help me solve this please:

27^x-3^(x+1)-3=0

Thanks in advance

Ps. it should be 0.68 but i dont know how to work it out

#2 2008-10-18 02:15:00

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Cubic Logarithms

Maybe I'm missing something, but I don't see how to get there analytically. The -3 messes stuff up.
You can get as close to the answer as you need to with a numerical method though.

Put a starting number into your calculator (say, 1).
Then do "log(3^(Ans+1)+3)÷(3log3)" and press equals lots of times until you're bored.


Why did the vector cross the road?
It wanted to be normal.

Offline

#3 2008-10-18 02:30:43

sce1912
Member
Registered: 2008-10-08
Posts: 5

Re: Cubic Logarithms

Hi DAN7891,

Do you need an exact solution or just an approximation?

An approximation can be achieved quite easily with trial and improvement

To get an exact answer you need to solve a cubic equation in 3^x this can be done(as cubics go the equation is relatively easy to solve)

I can post further details of how to solve the equation to get an exact answer if that is what's required.

Offline

Board footer

Powered by FluxBB