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ABCD is a cyclic quadrilateral.
E is the intersection of chord BC and AD.
Area of trianlge AEB is 1 square unit. then what is the area of of the circle.
What is the relation between area of triangle AEB and circle?
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You mean that E is the point of intersection of AD & BC"extended"?
Or did you mis-spell AC & BD for AD & BC?
Because AC & BD form the chords of the circle and intersect too but for chords AD & BC to intersect, they need to be extended to meet at some point outside the circle...
If two or more thoughts intersect, there has to be a point!
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Sorry the question is wrong. And sorry for not responding for long time.
Now the question is
We know that only one circle can be drawn which passes through all the vertex of a given triangle. So i concluded that there must be relation between the sides (and hence its area) of the triangle and the area of the circle. Is it my guessing wrong? If not what is the relation between the area of triangle and the area of the circle?
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