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Q 1. Find the absolute extrema of the function
f(x,y) = 5+4x-2x²+3y-y² on the triangular region with vertices (0, 0), (2, 2) and (-2, 2).
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Try working with f(x,y) = 10.25 - 2(x-1)² - (y-1.5)² instead.
Why did the vector cross the road?
It wanted to be normal.
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