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If f(4)=3 & f'(4)=-5, find g'(4). where g(x) = √x f(x)?
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Using the product rule, g'(x) = √x f'(x) + (1/2√x)f(x).
∴ g'(4) = 2*-5 + (1/4)*3 = -9 1/4
Why did the vector cross the road?
It wanted to be normal.
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Thanks .. Thanks Alot
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