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Can anyone help me understand how to solve this problem??? Thanks for the help.
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√2x-1 + √x+3 = 3
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I can't think how you'd solve a general problem like that, but this one is doable.
Both of the terms on the left are strictly increasing (making x bigger always makes them bigger), and so there can only be one value of x that fits.
That one value is fairly easy to find by guessing.
Edit: Ah, luca's done it properly. Squaring both sides still leaves a square root, but I didn't think to square again.
Why did the vector cross the road?
It wanted to be normal.
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trying both values in original equation shows that x = 1 is a solution, and x = 61 is invalid.
The Beginning Of All Things To End.
The End Of All Things To Come.
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Actually, x = 61 is valid. The original problem doesn't restrict us to positive square roots, so you get 11 + (-8) = 3.
Wrap it in bacon
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When square roots appear without a ±, this typically means you only take the positive root. Otherwise, just having the symbol "±" along with a square root would be redundant.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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