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wooooooow
good job,, JaneFairfax
,, thank you very much
your solution is perfectly true
,,
thanks again
Hey everybody,,,
can u help me with this question??
Find three positive numbers whose sum is 27 and such that the
sum of their squares is as small as possible.??
I think we need to use Partial Derivatives..
I really need the solution..
thanks..
hiiiiii JaneFairfax ,,,
thank thank thank you very much
you are really intelligent
but can you explain to me the first part I understand the second part of integration
but why you take the limit
we know that the integration at zero is undefined..
maybe the question is strange but I would like to know the exact meaning...
thanks again
hii all,,,
how r u??
My friend gave me a integral to solve
and I try but I couldn't,, I think that the question is wrong !!!
I think this integral is improper
see it
and try to help me to solve it
yes the final solution , in my opinion, 1/4
you need to use integration by parts
lol! has everyone gone nuts? Double integrals?
Let u = ln(x + 1)
let dv = x dx
its easy as pi!
then use substitution with (x+1)=u in second term of integral ( du*v)
if you don't understand yet
i can help you more
tell me my brother if you get
1. [sin(x-y)] / [cos(x+y)] = [tan(x)-tan(y)] / [1-tan(x)tan(y)]
Left side
now divide {numerator}{denominator} by cos(y)cos(x)
first simplify this expression
by usining division by -1 you will find f(x) = 0
thats means -1 is the first zero
you will get
divide by -1 again
and you can complete the answer
this limit is one of famous limits
you can solve this limit by l'Hopital's rule(if you don't know this rule tell me to explain it).
The limit of X --> 0 degrees of (Sin x)/X = 1
The limit of X --> 0 degrees of (tan x)/X = 1
The limit of X --> 0 degrees of (1-cosx)/X = 0
Examples
1.
apply LHòpitals rule.
2. note:Applying the rule a single time still results in an indeterminate form. In this case, the limit may be evaluated by applying l'Hôpital's rule three times:
apply
we get
then simplify
apply
we'll get
finally
hiii Joey
It's easy
and I'll try to explain my solution
firstly
subtract 5 from each side
3x + 5 - 5 = 8 - 5
3x= 3
then
divide each side by 3
x = 1
finally
thank you for visit
Toast
yes ,
I drew that's in paint,,
it was hard work,,:|
because I didn't knew anything about topic
:)
thank you very much,,
welcome
:)
thank you ALL
:D:cool::cool:
hmmmmmmmmmm,,
What multipied by 2^x-1 equals 2^3x-2 ?.
(2^x-1)(2^2x-1)=2^3x-2
2(2^x-1)^3=2^3x-2
= 2y^3
Is that a correct answer ?
pi man,,
I forgot that.
I'm sorry.
thank you for advice
RauLiTo
that's good...
nice to meet you here ..
:D
your brother
saudi_boy
Simplifying Simple i Terms - Intermediate Level
Express in simplest terms, in terms of i.
1. i[sup]1[/sup]
2. i[sup]3[/sup]
3. i[sup]0[/sup]
4. i[sup]19[/sup]
5. (i[sup]12[/sup])[sup]15[/sup]
6. i[sup]16[/sup] + i[sup]11[/sup]
7. i[sup]18[/sup] + i[sup]13[/sup]
8. (i[sup]6[/sup])[sup]30[/sup]
9. i[sup]25[/sup] - i[sup]20[/sup]
10. i[sup]29[/sup] × i[sup]14[/sup]
11. i[sup]23[/sup]
12. i[sup]36[/sup] ÷ i[sup]32[/sup]
13. i[sup]37[/sup] - i[sup]2[/sup]
14. (i[sup]28[/sup])[sup]33[/sup]
15. i[sup]8[/sup]
16. i[sup]34[/sup] × i[sup]44[/sup]
17. i[sup]50[/sup] + i[sup]40[/sup]
18. i[sup]49[/sup] ÷ i[sup]17[/sup]
-------------------
Answer,,
1. i
2. -i
3. i^o= 1
4. i^19 = i^3 = -i
5. 1
6. 1 - i
7. i^18 + i^13 = i^2 + i^1 = -1 +i
8. 1
9. i - 1
10. i^29 + i^14 = i^1 + i^2 = -i
11. i^23 = i^3 = -i
12. 1
13. i + 1
14. 1
15. 1
16. -1
17. 0
18. 1
:)
pi man
thank U very much,,,
polylog
yessssss,,
that's good work.
thank you veeeery much..