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#51 Re: Help Me ! » How to make up an equation » 2007-01-29 15:00:49

This is a little more of an explanation of what I need to do. Any help would be great.

Take the real-life situation you described (2005 & 2006 accidents) and create an equation or inequality that could be used for analysis, prediction, or decision making. Then, draw a graph to depict the variables in your situation. Use your graph and what you know about linear inequalities to discuss the significance of your findings

#52 Re: Help Me ! » How to make up an equation » 2007-01-29 13:15:16

What more info would be helpful? and how would I put % into an equation?

#53 Help Me ! » How to make up an equation » 2007-01-29 10:19:11

jxharmon
Replies: 7

If I have 66 accidents in 2005 and 47 in 2006, how do I find the estimated accidents for 2007 and what equation would I give?

#54 Re: Help Me ! » Can u explain Function Notation » 2007-01-29 09:03:29

Our professor was very fague on the question, but I think you have helped me enough to discuss intelligently:)

#55 Re: Help Me ! » Can u explain Function Notation » 2007-01-29 04:47:18

We are studying the system of linear equations.(value of x)

#56 Help Me ! » Can u explain Function Notation » 2007-01-29 04:22:54

jxharmon
Replies: 12

and reasons why it is important????

#57 Re: Help Me ! » 2 equations=parallel lines » 2007-01-26 15:15:10

so it would be y=-2x+2 and y=2x+2; right

#58 Help Me ! » Graph ? » 2007-01-26 07:39:45

jxharmon
Replies: 1

I have to graph by first solving for y.
4x - 3y=6

I came up with y=0, -2 and the slope 4/3. Am I right?

#59 Help Me ! » Equation ? » 2007-01-26 07:38:15

jxharmon
Replies: 3

How do I write an equation of the line with slope -2 and y-intercept (0,0)?

would it be
y=-2x or y= x -2

#60 Re: Help Me ! » 2 equations=parallel lines » 2007-01-26 07:35:25

So I show y=2x+2 & y=1/2x+2 are parrallel...is that correct?

#61 Re: Help Me ! » Table question. » 2007-01-26 01:36:04

Thank you, makes sense now.

#62 Help Me ! » graph inequalities » 2007-01-25 17:18:19

jxharmon
Replies: 1

3x-4y <12 I graphed the points (-4,-6);(4,0); and (0,-3) now I just don't know whether to shade above or below the line???

#63 Help Me ! » Line graphs??? » 2007-01-25 10:17:46

jxharmon
Replies: 1

These data represent the population of a certain city.
Year    Population (in thousands)
1950        18
1960        23
1970        29
1980        32
1990        38
2000        42                 
   
(a)  Draw a line graph for the data.
(b)  Use the line graph to predict the population in the year 2010.

Is it best to do graphs in excel or word? Mine are looking horrible!!!

#64 Help Me ! » Table question. » 2007-01-25 10:15:51

jxharmon
Replies: 2

Use the following tabe to answer the question.
Population of Europe by Age Groups
    Population (in thousands)
    1950    1970    1995
Age 0-14    143,175    166,367    139,464
Age 15-64    359,162    421,432    487,110
Age 65+    44,981    68,642    101,338
Age 75+    14,553    22,762    38,139
Total    547,318    656,441    727,912
Source: European Rural Development (ERD) Project.

What was the percentage increase in the age 75+ population of Europe from 1970 to 1995?

#65 Help Me ! » 2 equations=parallel lines » 2007-01-25 10:14:40

jxharmon
Replies: 8

Determine which two equations represent parallel lines.
(a)  y = –2x + 2    (b)  y = 2x + 2    (c)  y =  x + 2
(d)  y = –2x + 5

#66 Help Me ! » Can anyone help with equations? » 2007-01-25 10:11:33

jxharmon
Replies: 1

Write the equation of the line which passes through the point (2, 1) and is parallel to the line with equation y =5/2x + 6 .

#67 Help Me ! » is figure a parallelogram or rectangle » 2007-01-22 08:12:08

jxharmon
Replies: 1

the points on graph are (0,3),(2,0),(-1,-2),(-3,1)

is this the way to work this  m=1-(-2)/-3-(-1) =-1/2   m=0-3/2-0=-3/2

this would be a rectangle  would like to know if this is correct

#69 Re: Help Me ! » standard form equation » 2007-01-22 06:15:41

so then to write it in standard form would just be y=-3/5x+5 am I trying to make things complicated?

#70 Help Me ! » standard form equation » 2007-01-22 05:45:14

jxharmon
Replies: 4

write in standard form; (0,5), m=-3/5
y=mx + b          5=-3/5(0) +b        5=b       y=0.x+5         y=5
did I do this correct? or am I not getting something

#71 Re: Help Me ! » finding more y-intercepts » 2007-01-22 05:25:13

thanks alot so if slope is 5 and y-intercept: (0,-2)  y=5x -(-2); so I graph (0,-2) then slope is rise over run slope of  5 =5/1 so if x changes by 1 then y would change by 5 so y value would be 5(5-2) plot the point of (1,3) am I on the right track or did I not get something.

#73 Re: Help Me ! » geometry HELP! » 2007-01-22 04:47:56

thanks that help me get out of the rut

#74 Help Me ! » parallelogram or a rectangle » 2007-01-22 04:21:30

jxharmon
Replies: 1

it says used the concept of slope to determine if the given figure is a parallelogram or a rectangle.  I don't understand what that means. do I just count the boxes or find the points that the lines are passing through and if they are equal it is a parallelogram and if they are not it is a rectangle? Not Sure what to do or if there is a formula for finding

#75 Help Me ! » geometry HELP! » 2007-01-22 04:17:48

jxharmon
Replies: 2

floor plans for a building have four corners of a room located at the points (2,3),(11,6), (-3,18) and (8,21) determine whether the side through the points (2,3) and (11,6) is parallel to the side through the points (-3,18) and (8,21); then determine whether the side through the points (2,3) and (11,6) is perpendicular to the side through the points (2,3) and (-3, 18); I am so confused now I don't know where to begin. this is what I did hope to find if I am on the right track;

m=6-3/11-2 =3/9=1/3  and m= 18-3/-3-2=15/5=3 now I need to find out if it is perpendicular ?

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