Math Is Fun Forum

I started on the forum as an ordinary member and I helped a few folk with questions.  Then I was badly trolled because of an answer I gave.  I spent the next few days composing angry and sarcastic responses (in my head) . In the end I decided to just say nothing....

Hi amnkb;

sologuitar wrote:

What is the best way to solve tricky or lengthy word problems?

amnkb wrote:

best way to solve long or tricky word problems

Yes, good find!

A phone company charges $2 for the first five minutes of a phone call and 30 cents per minute thereafter. If Bill makes a phone call that lasts 25 minutes, what will be the total cost of the phone call?

Just answer the questions posted and keep your text math-related.

Devon owns a house cleaning company and has to give price quotes to potential customers. He figures out his price by assuming a $25 base charge and then adding $8 for each bathroom and $4 for each other room. If he uses P to represent the price, B for bathroom, and R for other rooms, create a formula to represent this situation.

Just answer the questions posted and keep your text math-related.

Company X sold 1,500 units of its product for $9 each and 750 units for $6 each. If the company's cost of producing each unit of the product was $7, what was the company's profit or loss on the sale of 2,250 units?

Just answer the questions posted and keep your text math-related.

There is always a way to solve problems without a calculator.

Is there an algebraic way to simplify this stuff?

don't think so
if wolfram alpha cant come up with an exact ans then you and me probably cant either

Again, just a question. No need to belittle anyone for asking questions that maybe others are hesitant to ask.

You can even specify exactly how much spacing you want. For example, if you want exactly 30 mm of white space,

\hspace{30mm}

Thus:

Use technology to obtain a decimal approximation. That is, use your calculator or an online resource such as Wolfram Alpha:

https://www.wolframalpha.com/input?i2d=true&i=Power%5B%5C%2840%29Sqrt%5B2%5D%5C%2841%29%2CSqrt%5B2%5D%5D

Is there an algebraic way to simplify this stuff?

Company X sold 1,500 units of its product for $9 each and 750 units for $6 each. If the company's cost of producing each unit of the product was $7, what was the company's profit or loss on the sale of 2,250 units?

So, 1,500 units at $9 each = $13,500.
Also, 750 units at $6 each = $4,500.
This together = $18,000.

Also 2250 units at $7 each = $15, 750.

The company's profit or loss is the confusing part for me.

Interesting. Because the first half dozen or so Google results I got said that factors can be negative.

It does seem right that they would count as factors. We're told that a factor is a number that when multiplied by certain other numbers gives us a particular product (2, when multiplied by 9, gives us the product 18). -2 and -9 seem to fit this criteria.

But I trust your good self, and this site generally, so I'm now doubting those Google results, and my own intution.

Who, or what body, is the ulitmate arbiter of these things? Is there an ultimate arbiter of these things?

open google play store
select 'search'
enter 'carbon browser'
select and install

This is too confusing.

which part? you installed carbon browser and then??

I am not a technical person. What is a carbon browser?