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harpazo1965 wrote:amnkb wrote:open google play store
select 'search'
enter 'carbon browser'
select and install
open carbon brwoser
enter url for image
long-press image
select 'open image in new tab'
go to new tab
press url box (it should look like i.imgur.io/[bunch of characters]_d.webp?[query string]
note: [bunch of characters] in the new tab will NOT be the same as the [bunch of characters] in the original tab!!!
select edit (pencil icon)
erase from the end until you get to the [stuff]_d.webp
replace .webp with .jpg
delete _d
select 'go' at bottom of keyboard
your image should diaply alone on the page
copy new url and paste between [ img] [ /img] tags (without the extra spaces of course)This is too confusing.
which part? you installed carbon browser and then??
I am not a technical person. What is a carbon browser?
1. Select a desired image.
2. Drag the image file.
3. Save the image as .jpg [img]and[/img].
You will get the required image with text.
For example,
Choose mango.
Cut and paste the link https://livekarts.in/wp-content/uploads/2021/05/mango.jpg.
Then the image will be displayed as
https://livekarts.in/wp-content/uploads/2021/05/mango.jpg.
What do you mean by drag the image? I have a cell phone not a computer.
harpazo1965 wrote:This is just a test. I want to know if anyone here can see the photo.
https://imgur.com/gallery/4Gh1VYy
i did copy n paste
is it supposed to be 'coney island parachute ride'?https://i.imgur.com/7uB3NEl.jpeg
If you could copy and paste moving forward, this is good enough for me.
Yes, the photo is correct.
harpazo1965 wrote:amnkb wrote:where did 1.4674 come from?
did you assign n the value of pi?
how did you get the square of n/4 being (n^2)/4?
shouldnt the 4 be squared too?
not understanding your results
sryLook:
-1 + π^2/4 = 1.4674 according to the calculator.
so n equals
?also the middle coefficient of your equation is (pi)/2
you're supposed to take half of this and then square it to get the third term to complete the square
the complete-the-squarr process is:half of b/a is b/2a
square this to get the completed-square 3erd term:half of (pi)/2 is (pi)/4
square this to get ((pi)^2)/16
unless they tell you specifically to round to 4 decimal places you should do exact using pi
x^2 + (π/2) x + π^2/16 = -1 + π^2/16
(x + (π/4))(x + (π/4)) = 1.4674
(x + (π/4))^2 = -0.38315
Stuck here....
A circular pool measures 10 feet across. One cubic yard of concrete is to be used to create a circular border of uniform width around the pool. If the border is to have a depth of 3 inches, how wide will the border be?
I know that 1 cubic yard is 27 cubic feet.
I say let x = width of the border around the pool
I don't know where to go with this information.
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
This one through me into a loop.
I think this problem demands the use of the volume formula
V = length • width • height. The part about reducing the volume by 10% is confusing to me.
Can someone explain what is going on in this problem and set up the right equation for me to use?
harpazo1965 wrote:Can you send me step be step instructions in terms of uploading photos and images?
okay i can expand on what i said before
open google play store
select 'search'
enter 'carbon browser'
select and install
open carbon brwoser
enter url for image
long-press image
select 'open image in new tab'
go to new tab
press url box (it should look like i.imgur.io/[bunch of characters].webp?[query string]
note: [bunch of characters] in the new tab will NOT be the same as the [bunch of characters] in the original tab!!!
select edit (pencil icon)
erase from the end until you get to the .webp
replace .webp with .jpg
select 'go' at bottom of keyboard
your image should diaply alone on the page
copy new url and paste between [ img] [ /img] tags (without the extra spaces of course)with your image from another thread i got this:
i.imgur.io/7uB3NEl_d.jpg
remove the '_d' to get i.imgur.io/7uB3NEl.jpg
putting it between the 'img' tags does this:https://i.imgur.io/7uB3NEl.jpg
if you dont delete the underscore-d then you get a thumbnail (?) thats pretty small:
https://i.imgur.io/7uB3NEl_d.jpg
This is too confusing.
harpazo1965 wrote:amnkb wrote:where did 1.4674 come from?
did you assign n the value of pi?
how did you get the square of n/4 being (n^2)/4?
shouldnt the 4 be squared too?
not understanding your results
sryLook:
-1 + π^2/4 = 1.4674 according to the calculator.
so n equals
?also the middle coefficient of your equation is (pi)/2
you're supposed to take half of this and then square it to get the third term to complete the square
the complete-the-squarr process is:half of b/a is b/2a
square this to get the completed-square 3erd term:half of (pi)/2 is (pi)/4
square this to get ((pi)^2)/16
unless they tell you specifically to round to 4 decimal places you should do exact using pi
Ok. I see that my first mistake was squaring wrongly.
Can you finish this one for me?
harpazo1965 wrote:(-1)^2 + 6(-1) = (1) - 6 = -5
(-5)^2 + 6(-5) = (25) - 30 = - 5
The correct of a is -5.
why do you say a = -1 is not a sol'n?
Why? I was rushing through the math work.
Answers: a = -5, a = -1
harpazo1965 wrote:Given 16y^2 = 120x - 225,
A. Find the intercepts.
B. Test for symmetry with respect to the x-axis, y-axis, and origin.
For A, I simply let x = 0 to find the y-intercept(s).
To find find x-intercept(s), I must let y = 0.yes
harpazo1965 wrote:Yes, it's symmetric with respect to the x-axis.
I say not symmetric with respect to the y-axis.
I say not symmetric with respect to the origin.
check your work with a graph
its a sideways parabola so its only symmetric abt the x-axis
desmos graph
Thank you for the graph. It helps out in many ways.
harpazo1965 wrote:An equation is being tested for symmetry with respect to the x-axis, y-axis and the origin. Explain why, if two of these symmetries are present, the remaining one must also be present.
Does anyone know?
Reddit thread
if its symmetric about the y-axis then its even
if its symmetric about the origin then its odd
so the equation cant be a function
maybe theyr'e thinking of circles/ellipses?
symmetry PDF
I have no idea. If I don't show effort it pretty much means I have no clue how to begin answering the question.
harpazo1965 wrote:If the graph of an equation is symmetric with respect to the x-axis and 2 is a y-intercept, name the other y-intercept.
A graph is said to be symmetric with respect to the x-axis if, for every point (x, y) on the graph, the point (x, -y) is also on the graph.
I say the other y-intercept is the point (0, -2).
yes
It looks like I'm cooking with gas.
harpazo1965 wrote:If the graph of an equation is symmetric with respect to the y-axis and 6 is an x-intercept of this graph, name another x-intercept.
I know that a graph is said to be symmetric with respect to the y-axis if, for every point (x, y) on the graph, the point (-x, y) is also on the graph.
I say another x-intercept is the point (-6, 0).
yes
It feels good to be right.
harpazo1965 wrote:If (a, -5) is a point on the graph of y = x^2 + 6x, what is a?
-5 = a^2 + 6a
a^2 + 6a + 5 = 0
(a + 1) (x + 5) = 0
a = -1
a = -5
I got two values for a. Which one is right? Are they both right?
quadratics usually have 2 sol'ns
to check your ans plug it back into the problme
what does (-1)^2 + 6(-1) equal
what does (-5)^2 + 6(-5) equal
(-1)^2 + 6(-1) = (1) - 6 = -5
(-5)^2 + 6(-5) = (25) - 30 = - 5
The correct of a is -5.
harpazo1965 wrote:Find the intercepts given the equation 5x + 2y = 10.
To find the x-intercept let y = 0.
5x + 2(0) = 10
5x = 10
x = 2
To find the y-intercept, let x = 0.
5(0) + 2y = 10
2y = 10
y = 5
you can check your work by graphing
y = -(5/2)x + 5
Already checked it out.
harpazo1965 wrote:x^2 + (π/2) x + π^2/4 = -1 + π^2/4
(x + (π/2))(x + (π/2)) = 1.4674
(x + (π/2))^2 = 1.4674
I now take the square root on both sides. Yes?
where did 1.4674 come from?
did you assign n the value of pi?
how did you get the square of n/4 being (n^2)/4?
shouldnt the 4 be squared too?
not understanding your results
sry
Look:
-1 + π^2/4 = 1.4674 according to the calculator.
harpazo1965 wrote:The midpoint of the line segment from A to B is (5, -4). If B = (7, -2), what is A?
Solution:
Let point A = (x_1, y_1).
5 = (x_1 + 7)/2
-4 = (y_1 - 2)/2
Is this the correct set up to find the coordinates of point A?
this is fine
you can check your work by using the distance formula
if |AB| is twice as long as |CB| (i'm naming the midpoint C) then your answer is right
Ok. Very good.
Can you send me step be step instructions in terms of uploading photos and images?
A little progress:
Probabliity of 4 aces in 13 cards is {choose 1st = 4} then {second = 3} then {third = 2} then no choice for the last. Then choose 10 non aces. Finally, the aces may occur in any spaces within the thirteen slots so 13 C 4
Continuing to cancel factors:
So where do the other two terms come from?
Bob
Can you send me step be step instructions in terms of uploading photos and images?
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3. I've been to therapists my whole life. I find the less attention I pay to food, the healthier I am. Any obsession is dangerous. And a whole country that's obsessed with one thing, unless it's, like, jeans, it's very dangerous. Everyone's obsessed right now with carbohydrates in this country. It's ridiculous. - Christina Ricci
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https://medlineplus.gov/images/Carbohydrates.jpg
Can you send me step be step instructions in terms of uploading photos and images?
This is just a test. I want to know if anyone here can see the photo.
https://imgur.com/gallery/4Gh1VYy
An equation is being tested for symmetry with respect to the x-axis, y-axis and the origin. Explain why, if two of these symmetries are present, the remaining one must also be present.
Does anyone know?
Given 16y^2 = 120x - 225,
A. Find the intercepts.
B. Test for symmetry with respect to the x-axis, y-axis, and origin.
Let me see.
For A, I simply let x = 0 to find the y-intercept(s).
To find find x-intercept(s), I must let y = 0.
You say?
Part B
To test for symmetry with respect to the x-axis, I must replace y with with -y.
Let's see.
16(-y)^2 = 120x - 225
16y^2 = 120x - 225...I got the original equation.
Yes, it's symmetric with respect to the x-axis.
To test for symmetry with respect to the y-axis, I must let x be -x
16y^2 = 120(-x) - 225
16y^2 = -120x - 225
I say not symmetric with respect to the y-axis.
To test for symmetry with respect to the origin, I must let y be -y and x be -x.
16(-y)^2 = 120(-x) - 225
16y^2 = -120x - 225
I say not symmetric with respect to the origin.
You say?
If the graph of an equation is symmetric with respect to the x-axis and 2 is a y-intercept, name the other y-intercept.
Let me see.
A graph is said to be symmetric with respect to the x-axis if, for every point (x, y) on the graph, the point (x, -y) is also on the graph.
I say the other y-intercept is the point (0, -2).
You say?
If the graph of an equation is symmetric with respect to the y-axis and 6 is an x-intercept of this graph, name another x-intercept.
I know that a graph is said to be symmetric with respect to the y-axis if, for every point (x, y) on the graph, the point (-x, y) is also on the graph.
I say another x-intercept is the point (-6, 0).
You say?
If (a, -5) is a point on the graph of y = x^2 + 6x, what is a?
Let me see.
Let y = -5
Let x = a
-5 = a^2 + 6a
a^2 + 6a + 5 = 0
Factor.
(a + 1) (x + 5) = 0
a + 1 = 0
a = -1
a + 5 = 0
a = -5
I got two values for a. Which one is right? Are they both right?
You say?