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You will see in this way. When you divided it into 3 triangle, the sum of interior is actually the sum of the interior of the 3 triangles , so 3*180=540 degree
I clicked the square at Level 7 but nothing happened.
clicking the inside of the squre doesnt work, you need to click on the line of the squre
ok, since this thread is too long, I'll just repost my calculation next to Luis'
Can you describe this part |cos x +|3 in word, I could make it into latex but I must understand it first
Dont understand this pat |cos x +|3
I believe they are equal, cuz you cant find any number larger than 0.99999999.... and less than 1
I dont know much about congruence
I looked up the al-Haytham theorm on Wiki
(p-1)! = -1 (mod p)
knowing that (p-2)!(p-1) = -1 (mod p)
(p-1) = -1 (mod p)
Thus (p-2)! =1 (mod p)
I am not sure if its correct lol
Level 20 is so unfair...
How about
You connect those points, then you could compare the graph to other types of funcions'
For 3x could only choose (-5 ,4). -1 could choose (3x,4) and (-5,3x)
3x*(-5)*4+(-1)*3x*4+(-1)*(-5)*3x = -60x-12x+15x=-57x
I'll leave the second one to you
Ah, I see, thx
ok, what bothers me is that last step, It seems that I cant get x>N, since (x-N)^2>0 , is valid for whaever value of x and N
I tried to prove this, but it doesnt seem satisfying (The last step)
How about considering them lying on the same plane
C and C_2 can be calculated, I think the point is the intersection of two circles and it lies inside the triangle?
still thinking about it ..XD
http://myanimelist.net/animelist/dragonshade
That's my anime list, if I score 10 , that means those are my favs, ^^
In my opinion, 3 points could determine a plane in a 3D space, since the 3 particle are in equilibrium, you could put the fourth particle as a point in inside the triangle, and with the same distance to all 3 particles, that point should be the center of a circle inscribing the triangle
I watched over a hundred TV series of animes........
Luis is right
But I test it with C++ , I got 374 as well
#include <iostream>
using namespace std;
int main()
{
int n=3;
int Sum=0;
do
{
n=n+7;
Sum = Sum+n;
}while (Sum < 10000);
cout << n;
return 0;
}
correct me if I am wrong