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Find a set of parametric equations that represents the graph of y=√ x+4, using the parameter t=1+x/4
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Make x the subject of its equation first:
t = 1 + x/4
t-1 = x/4
x = 4(t-1)
Then substitute that into the y equation to get y in terms of t.
y = √(x+4)
y = √(4(t-1)+4)
y = √(4t)
y = 2√t
Why did the vector cross the road?
It wanted to be normal.
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