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At what point does the graph of
y = 1/√x have a tangent line parallel to the line
x + 16y = 5?
Seeking steps here.
If the tangent line is parallel to the line x + 16y = 5, it must have the same slope.
What is the slope of x + 16y = 5?
Let me see.
I must solve for y to make the equation look like y = mx + b.
16y = -x + 5
y = (-x + 5)/(16)
The slope is -1/16.
Stuck here....
Last edited by mathland (2021-05-10 14:23:22)
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You're going to need to differentiate y = 1/√x and set that equal to -1/16
B
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You're going to need to differentiate y = 1/√x and set that equal to -1/16
B
Ok. I can do that, really.
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