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#1 2021-05-10 14:22:50

mathland
Member
Registered: 2021-03-25
Posts: 444

Find Point

At what point does the graph of
y = 1/√x have a tangent line parallel to the line
x + 16y = 5?

Seeking steps here.

If the tangent line is parallel to the line x + 16y = 5, it must have the same slope.

What is the slope of x + 16y = 5?

Let me see.

I must solve for y to make the equation look like y = mx + b.

16y = -x + 5

y = (-x + 5)/(16)

The slope is -1/16.

Stuck here....

Last edited by mathland (2021-05-10 14:23:22)

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#2 2021-05-11 08:22:35

Bob
Administrator
Registered: 2010-06-20
Posts: 10,052

Re: Find Point

You're going to need to differentiate y = 1/√x and set that equal to -1/16

B


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2021-05-11 10:31:19

mathland
Member
Registered: 2021-03-25
Posts: 444

Re: Find Point

Bob wrote:

You're going to need to differentiate y = 1/√x and set that equal to -1/16

B

Ok. I can do that, really.

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