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Hi I want to show that for x>3
(x^5 - 1)/(x-1) ≠ y^2
where y is any integer
basically the expression is not a perfect square
I've tried proof by induction but can't seem to get anywhere
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Are you sure you're supposed to use induction? It may be possible, but don't see a good way of solving the problem with it. I would go for a more direct approach.
First, let's simplify the expression. The LHS is equal to
for all x other than x=1. Since we're only interested in x>3, we can use this simplification.
Let's assume that this expression is a perfect square. That means we can factor it as follows:
Solve for a, b, c:
Wrap it in bacon
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no, a value for a polynomial can be a perfect square, without the polynomial being a perfect square of a polynomial...
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Hi Kurre;
I'm not following you. When x=3, f(3) = 121 is a square.
Last edited by bobbym (2009-05-20 17:13:04)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I'm not following you. When x=3, f(3) = 121 a square.
This exactly illustrates Kurre's point. TheDude's post presents a proof that the polynomial
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Sorry Kurre and thanks Avon;
I get it now. So, the original question still remains unproved?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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