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#1 2005-11-23 23:52:04

morik
Member
Registered: 2005-11-23
Posts: 16

Hello there. Anyone help me?

Hey, I study computing and have a small Math module to do over the weekend. (The most feared unit on all my course for me as I never have had a good mind for maths.

Anyway, here are some questions that are bugging me...
Could anyone please tell me either the answers and/or the steps of working them out?


1. (Please note the cubed symbols have minus' before them in this one) Calculate 2 x 10-³ x 3 x 10-³

2. Binary to denary conversion. Convert 11111110 divided by 2

3. Calculate: 22 1/3rd
                   ¯¯¯¯¯¯¯
                   3 3/8ths

4. Calculate 22 1/3 -  3 3/8

5. (22 1/3 / 3 3/8) + 22 1/3

Thanks for taking time to help smile
Dani

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#2 2005-11-24 00:08:41

Jai Ganesh
Administrator
Registered: 2005-06-28
Posts: 48,402

Re: Hello there. Anyone help me?

Answers:-

1. 6 x 10^(-6) i.e. 6 x 1/100,000 = 0.000006

2. Question not clear. Is it convert 11111110 into binary, then divide by 2?

3. 22 1/3 = 67/3, 3 3/8 = 27/8;   67/3 divided by 27/8 is
67/3 x 8/27 = 536/81.

4. 67/3 - 27/8 = [536-81]/24 = 455/24

5. Result of 3 + 22 1/3 = 536/81 + 67/3 = [536*3 + 81*67]/243
= 7035/243 = 2345/81

[*** in a hurry...didn't check for errors!***]


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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#3 2005-11-24 00:22:42

morik
Member
Registered: 2005-11-23
Posts: 16

Re: Hello there. Anyone help me?

That's awesome. Thanks a lot for that speedy reply. Don't worry about that binary question. I think i sussed it. smile

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#4 2005-11-24 04:41:54

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Hello there. Anyone help me?

I think the binary one is 11111110 (bin) ÷ 2(dec) = ?(dec)

Anyway, 2 in binary is 10 and so the first part is really easy, you just knock off the 0.

11111110 ÷ 10 = 1111111.

Then, to convert that into decimal, assign each 1 its power-of-2 value.

1111111 --> 1+2+4+8+16+32+64 = 127.


Why did the vector cross the road?
It wanted to be normal.

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