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Find the foci and vertices for y^2/36+x^2/9=1
I got it as(0,4) and vertices (12,9)
I used the (x-h) and (y-k) form and found the ans.
But, my teacher told it is wrong. Does anybody knows this?
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hi Dharshi
Just checking ... you mean
That would be an ellipse.
major axis = 2a = 12
minor axis = 2b = 6
so eccentricity = e where
and the foci are at ±ae
But what do you mean by the vertices?
At http://www.mathwords.com/v/vertices_of_an_ellipse.htm it says they are at the ends of the major axis, so (0,6) and (0,-6)
Bob
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