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X'(y-Xβ)=0
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Couldn't that be re-written as:
I havn't had much experience with lim, and can't remember what it signifys. What exactly is your question?
Edit: Upon refreshing my memories with limits (The almighty Wikipedia ) The formula I specified is incorrect. I don't know if you already know what your formula does or not. Could supply a bit more information? As far as I can tell, your forumla is getting as close to zero as possible and then bigger at a slower rate depending on the size of n.
If you were to make n = 900. It would make the sum of:
Where i was increasing from 1 until it reached 900.
Last edited by Zmurf (2006-05-14 19:18:31)
"When subtracted from 180, the sum of the square-root of the two equal angles of an isocoles triangle squared will give the square-root of the remaining angle squared."
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Good.
The interesting here is that n is in non-trivial place in the sum.
IPBLE: Increasing Performance By Lowering Expectations.
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...I think...:)
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From Excel. Notice the interesting pattern. This may help us rewrite the equation.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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A plot:
Last edited by krassi_holmz (2006-05-14 20:28:39)
IPBLE: Increasing Performance By Lowering Expectations.
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Good.
The interesting here is that n is in non-trivial place in the sum.
Yes, you are smart!
To Zmurf and Krassi:
Originally it's a Rieman Sum, an integration question. So I guess Krassi has used integral.
Original Question:
Last edited by George,Y (2006-05-15 15:21:13)
X'(y-Xβ)=0
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???
That's A Limit!!!
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Yes, and that does return a limit result log2
X'(y-Xβ)=0
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I'm from Beijing China.
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How do you transform it into a Rieman Sum? There is no Δx or another 1/n in it!
The integral is indeed a limit if you admit the property of Delta Function:
where
Last edited by George,Y (2006-05-20 21:16:17)
X'(y-Xβ)=0
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Here's a SUM (I actually need it for a question):
Find:
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The sum of the reciprocal of every prime to power n?
Download some primes from here: Prime Number List
Then put into Excel.
For Primes up to 100,000
n=1: 2.705272179
n=2: 0.452246618
n=10: 0.000993604
n=20: 9.53961E-07
So that seems to be heading for 0, but then there are infinitely many primes, not just the 9,500 in the list.
(The "2.70" for n=1 is interesting)
(Here's another thought, it will be less than the same sum over positive integers)
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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oh...my English is poor..so i can not express what i think sometimes.:D but i'm very sure my answer is right.:P
on the image:
Last edited by liuv (2006-05-21 02:46:48)
I'm from Beijing China.
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Thank you liuv, good shifting! My thought is
for krassi holmz,
you may check out some properties for prime numbers.
PS> how did you put "n->∞" under "lim"?
Last edited by George,Y (2006-05-22 02:31:16)
X'(y-Xβ)=0
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Like that. Basically, put a \ before lim.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Yep.
\lim_{n \to \infty}
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but then there are infinitely many primes, not just the 9,500 in the list.
That's my point that you can't compute the lim directly- for different number of the primes you'll get different result.
IPBLE: Increasing Performance By Lowering Expectations.
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thanks a lot!
X'(y-Xβ)=0
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