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This one on page 49 is not a difference of cubes. It's more challenging.
Can you do this one for me?
Problem 104; page 49.
Divide x^5 - a^5 by x - a.
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Ok. First notice that putting x=a causes x^5 - a^5 to become 0, so (x-a) is a factor => no remainder.
x^4 + a x^3 + a^2 x^2 + a^3 x + a^4
_____________________________________________________
x - a | x^5 + 0 x^4 + 0 x^3 + 0 x^2 + 0 x - a^5
x^5 - a x^4
______________
a x^4 + 0 x^3
a x^4 -a^2 x^3
___________________
+ a^2 x^3 + 0 x^2
+ a^2 x^3 - a^3 x^2
_________________________
+ a^3 x^2 + 0 x
+ a^3 x^2 - a^4 x
_____________________
+ a^4 x - a^5
+ a^4 x - a^5
_______________
remainder = 0 0
so x^5 - a^5 = ( x^4 + a x^3 + a^2 x^2 + a^3 x + a^4)(x-a)
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Ok. First notice that putting x=a causes x^5 - a^5 to become 0, so (x-a) is a factor => no remainder.
x^4 + a x^3 + a^2 x^2 + a^3 x + a^4
_____________________________________________________
x - a | x^5 + 0 x^4 + 0 x^3 + 0 x^2 + 0 x - a^5
x^5 - a x^4
______________
a x^4 + 0 x^3
a x^4 -a^2 x^3
___________________
+ a^2 x^3 + 0 x^2
+ a^2 x^3 - a^3 x^2
_________________________
+ a^3 x^2 + 0 x
+ a^3 x^2 - a^4 x
_____________________
+ a^4 x - a^5+ a^4 x - a^5
_______________remainder = 0 0
so x^5 - a^5 = ( x^4 + a x^3 + a^2 x^2 + a^3 x + a^4)(x-a)
Bob
I must say that you really know how to do long division by trying on different spaces in the typing area.
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