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three students must be chosen to serve on a panel out of a class of 12 students . in how many different ways can they be chosen?
well 12 students in total
1 2 3 4 5 6 7 8 9 10 11 12
3 must be chosen
so it can be
123
456
789
10 11 12
or
234
567
89 10
11 12 1
or
345
678
9 10 11
12 1 2
correct
so there are 12 ways
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What about 235, 236 etc and all other combinations?
Sorry I don't know the formulas, I never did stats, something to think about
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guyssssssssssssssssssssss help
ok tell me do u have to multiply the numbers to get teh answer ? and then divide by 3? no right
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The number of ways of choosing 3 items from a group of 12 is given by 12C3, which is:
12! /[3! * (12-3)!] = 220.
Why did the vector cross the road?
It wanted to be normal.
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thank u soooo much.
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