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does anyone know how i would answer a question like the following?
Let X be the outcome when a fair die is rolled once. Before the die is rolled you are offered either a guarenteed amount:
what is the best strategy to accept the guaranteed amount or gamble?
Last edited by EMPhillips1989 (2008-02-14 04:16:55)
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what
Put it in diffrent words?
You need to find the amount that you would expect to win if you gambled (so, the average win if you played lots and lots of times).
Rolling a 1 gets you 1/1 pounds, rolling a two gets you 1/2, and so on.
With 6 trials, you would expect to throw each value once, and so the amount you would expect to win is:
This works out to be 49/120 = 0.408..., or roughly 41p.
The safe amount converts to roughly 43p, which means it's the slightly better option.
Why did the vector cross the road?
It wanted to be normal.
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