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But my book says
Thanks.
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You're not wrong, you just need one more step to get the answers to match.
Use the same trick that you did to get from line 4 to 5.
Why did the vector cross the road?
It wanted to be normal.
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Ahh okay, thanks
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Hi Daniel. I don't get this:
Could you explain it please? :)
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The sum of the nth roots of unity will always give 0. Proof:
This can also be 'seen' if you think of each of the roots as vectors. The argument of each root increases by 2pi/n each time, so adding n of them will give a regular polygon with n sides, returning to the starting point (ie a vector sum of zero).
Actually, this isn't just true for nth roots of unity; it's true for nth roots of all complex numbers.
Last edited by Daniel123 (2008-11-24 11:19:42)
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Ahh I didn't know that
were the nth roots of unity. Now it makes perfect sense. Thanks!(typo)
Last edited by Nils-Ake (2008-11-25 00:38:21)
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