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#26 Help Me ! » Equation solving wht next? » 2006-12-28 04:50:53
- Kiran
- Replies: 10
solve the following equation by completing the square:
9x^2 + 3x - 8 = 0
divide by 9
9/9 = 1
3/9 = 1/3
8/9 = 8/9
x^2 + (1/3)x - (8/9) = 0
add 8/9
x^2 + (1/3)x = (8/9)
(1/3)/2 = 1/6
(1/6)^2 = 1/36
add 1/36 both sides
x^2 + (1/3)x + (1/36) = (8/9) + (1/36)
( x + (1/6))^2 = (8/9) + (1/36)
(x + (1/6))^2 = (8/9) + (1/36) = 32/36 + 1/36 = 33/36 = 11/12
(x + (1/6))^2 = 11/12
x^2 + (1/6))^2 = 11/12
x^2 + 1/6^2 = 11/12
x^2 + 1/36 = 11/12
11/12 - 1/36 = 8/9
x^2 = 8/9
#27 Re: Help Me ! » two player » 2006-12-28 04:02:55
Yup thats the exact answer i got last night when i was doing it.
but i did it a different way.
i wrote
1 2 3 4 5
and paired it up
like
12
34
45
42
41
and etc.....and there are only 10ways i got
thanks btw
#28 Help Me ! » two player » 2006-12-27 11:16:46
- Kiran
- Replies: 5
how many different two player thumb-wrestling teams could be formed from 5 players?
#29 Re: Help Me ! » Relatively prime » 2006-12-27 05:04:14
thank you very much
#30 Re: Jokes » who loves animals » 2006-12-27 04:53:32
SAME WITH ME.........
but some dogs are vvvvvvvvvvv cute 
#31 Re: Help Me ! » Relatively prime » 2006-12-27 04:51:49
Oh my god i messed up Uffff ALLAh
its 42 not 422
sorry
#32 Help Me ! » Relatively prime » 2006-12-27 03:56:48
- Kiran
- Replies: 8
are the numbers 153 and 422 " relatively prime"?
#33 Help Me ! » sites » 2006-12-27 03:38:30
- Kiran
- Replies: 3
for problems like these
graph the following function by determining the region of interest:
y = x^3 - 2x + 1
and
given the function, y = 2x^3 - 3x + 2, find the y- intercept and sketch its graph.
i can use this site:
http://www.coolmath.com/graphit/index.html
and just put
x^3 ....... and it'll show me how to graph it
right?
#34 Help Me ! » Correct? » 2006-12-27 03:15:09
- Kiran
- Replies: 1
solve
7^(2x + 3) = 5^(3x - 1)
so
log7^(2x + 3) = log5^3x - 1)
(2x + 3) log7 = (3x - 1) log5
(2x + 3) (0.84509804) = (3x - 1) (0.698970004)
1.69019608x + 2.53529412 = 2.096910012x - 0.698970004
-0.406713932x = -3.234264124
x = 7.952184249
or
x = 8.0
#35 Help Me ! » Logs » 2006-12-26 06:51:21
- Kiran
- Replies: 2
Solve for x
log_6 9x - 2log_6 3 = 1
#36 Help Me ! » need more help » 2006-12-26 04:49:52
- Kiran
- Replies: 2
Use the remainder theorem to evaluate 2x^3 - 5x^2 + 2x + 5 when x = -2
ok i only got up to here i dont know what else to do
p(-2)
-2 | 2 -5 2 5
___ -5
#37 Help Me ! » anti log » 2006-12-26 04:45:57
- Kiran
- Replies: 2
anti log_3(-2)
i did
3^-2 which is 1/3^-2
1/ 0.111111111 = 9.000000009 or 10
and 10 is teh answer
#38 Re: Introductions » hello » 2006-12-26 04:26:05
PAKISTANI OFCOURSE
and you?
hey devante nice avatar...how u did that?
#39 Re: Dark Discussions at Cafe Infinity » Merry XMas 06 » 2006-12-22 11:04:59
Hey Merry Xmas to you too..
#40 Re: Introductions » Hi » 2006-12-21 09:17:22
oh god yeah i just saw the date..hehe ok
#41 Re: Jokes » who loves animals » 2006-12-21 08:54:51
Back In Vacations When I Went To India,
When A Silly Kitten Came, I Began Jumping On The TableI Am Afraid Of All Animals,wild+domestic
lol same with me... cats are ok..but i get real scared even when the other person says no its ok it wont bite ...still doesnt matter
#42 Re: Introductions » Hi » 2006-12-21 08:25:49
Welcome ricky....great intro
#43 Re: Help Me ! » Triangle » 2006-12-21 08:24:33
ok guys i dont know...
can you show me what you might think will be the way in solving the problem?
#44 Re: Help Me ! » Triangle » 2006-12-21 08:14:26
ok in my book they have the exact same question but offcourse with different numbers.
now i dont understand if we have such as in the book they have 0.5=cos x
and they said x = 60 degrees , 300 degrees and then they said x is less than 90 degrees so x = 60 degrees
how can i find the degrees of my problem?
#45 Re: Help Me ! » Triangle » 2006-12-21 05:22:15
can you help me out please?!
#46 Re: Help Me ! » Triangle » 2006-12-21 05:21:12
oh god yeha..i forgot to put 11........thanks for reminding me
#47 Re: Help Me ! » Triangle » 2006-12-21 04:56:02
well i dont know...thats how they did it in the book
#48 Re: Help Me ! » A - B » 2006-12-21 04:34:00
and i think the way you did it is has to be
2 2
2 0
not
2 0
2 2
so the answer would come out to
0 -3
0 -2
right?
#49 Re: Help Me ! » A - B » 2006-12-21 04:23:30
oh right this is the way ..thanks
but like is said
_ _ _ _
| 2 2 | | 2 5 |
| 2 0 | | 2 2 |
you see that there is a line on the five and there are lines liek this _ in teh problem what do they mean? nothing?
#50 Help Me ! » Triangle » 2006-12-21 04:20:38
- Kiran
- Replies: 10
solve for x and y
*
* y *
* dg *
8 * * 10
* *
* *
* *
* *
* *
* *
* x degrees *
********************************
11
I did .. but i need your help!
p^2 = a^2 + b^2 - 2ab cos P
8^2 = 10^2 + 11^2 - 2 (10)(11) cos X
64 = 100 + 121 - 220 cos X
64 = 221 - 220 - cos X
221 - 64 = 157
157 = 220 cos X
0.7 = cos X
how many degrees is that?
and i know i have ot do this when i find teh degrees .....
to find y
8/sin(x) = 11/sin y
sin y = 11sin(x)/8
sin y = ________
and how much degrees is that?
PELASE HELP ME OUT