Math Is Fun Forum

you find the image in an indicent

23.1/2.1=11

what hang man told me is that spelling errors lead to public execution

lol your a math guy not a physics guy so i guesss a half of 0 would be fine for you
in physics its important to know that heat is based on kelvin so  if you have double heat(and same medium) you have double kelvin readings but not nessecary double farenheight readings,and impossible to have double celcius readings

-812-10x-sin(xy)/2.362x

first you get rid of fractions
5x^3+12=0
then take the cube root
x^3=-12/5
x=pow(-12/5,1/3)
done!
ps:my method does not involve quadratic formulas so there may be some lost roots
edit:sorry!wrogn math!
first you get rid of fractions
5x^3+10x^2=-2
then you factor out 5x^2
x^2(x+2)=2/5
then you search google for third degree formulas and get desperate and call for help
@bob ~

oohay ive redid my math
F=ma=md²r/dt²=Gmm/r²(r is an imaginary number of position)
so we get a second order differential equation d²r/dt²=Gm/r²(the two “small object mass” cancel out)
the problem is that r is a function of time which is the solve to this diff equation
then move every d²r to left and every dt² to right
r²d²r=Gmdt²
integrate both sides
∫∫r²d²r=Gm∫∫dt²
1/3∫r³dr=Gm(mysteriously,nothing is in the right integral so its a moot point and we should ignore it)
r^4/12=Gm
so r=pow(Gm/12,1/4)
what this doesn't tell us is what direction we are going,but atleast we get the linear formula
next we should actually calculate the purely complex number(i.e really complex,like no lack of any part) r
r is replaced with a+bi
<strike>(a+bi)(a+bi)d²(a+bi)=Gmd²t
integrate them
∫∫(a²+2abi-b²)d²(a+bi)=Gm(again,no thing in right integral,so ignore)
∫∫(a³+3a²bi-3ab²-b³i)d²=Gm
∫(1/4a^4+1/2a³b²i-1/2a²b³-1/4b^4i)d=Gm
1/20a^5+1/24a^4b³i-1/24a³b^4-1/20b^5i=Gm
merge likes
(1/20a^5-1/24a³b^4)+(1/24a^4b³-1/20b^5)i=Gm</strike>

whoops wrong math
(a²+b²)d²(a+bi)=Gmd²t
integrate
∫∫(a²+b²)d²(a+bi)=Gm
∫∫(a³+a²bi+b²a-b³)d²=Gm
∫(1/4a^4+1/6a³b²i+1/6b³a²-1/4b^4)d=Gm
(1/20a^5-1/20b^5)+(1/72a^4b³+1/72a³b^4)i=Gm
there it goes
but there is the problem:where is the t?im expecting the varible time in my formula!
also the original problem probably did not involve 5th powers

Hello?
I know that this isn't an ims but its not an eternity messaging service either

Six is six,although its not clear why you would want TWO exclamation marks after it(not an exiting number after all)
just joking
720

He's attracting help,just like saying "a mathmatician is trying to solve this mysterious equation,what happens next would shock you" or "test ur iq!99.999999999% of ppl cannot complete it!"
Obviously this is bad,unethical,and maybe even a violation of forum rules(also this is not ims so this guy should not expect an answer that fast)