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If (x^²)^²= 16, what is the value of x?
Well, (x^2)^2 becomes x^4.
x^4 = 16
Take fourth root on both sides of the equation.
4root{x^4} = 4throot{16}
x = 2, x = -2
There are two values of x because I had to take the fourth root. If the fourth root was the given problem, then x = 2.
Is this a good explanation?
Last edited by Oculus8596 (2024-09-23 03:29:07)
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Yes, good. If you ever get to complex numbers you will discover there are also 2 complex values that work.
Bob
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Yes, good. If you ever get to complex numbers you will discover there are also 2 complex values that work.
Bob
I will post complex numbers in due time. Math is the only subject that keeps my brain cells alive.
The best things in life are not always free.
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