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**Oculus8596****Banned**- From: Great Lakes,Illinois
- Registered: 2024-09-18
- Posts: 126

If (x^²)^²= 16, what is the value of x?

Well, (x^2)^2 becomes x^4.

x^4 = 16

Take fourth root on both sides of the equation.

4root{x^4} = 4throot{16}

x = 2, x = -2

There are two values of x because I had to take the fourth root. If the fourth root was the given problem, then x = 2.

Is this a good explanation?

*Last edited by Oculus8596 (2024-09-23 03:29:07)*

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 10,610

Yes, good. If you ever get to complex numbers you will discover there are also 2 complex values that work.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**Oculus8596****Banned**- From: Great Lakes,Illinois
- Registered: 2024-09-18
- Posts: 126

Bob wrote:

Yes, good. If you ever get to complex numbers you will discover there are also 2 complex values that work.

Bob

I will post complex numbers in due time. Math is the only subject that keeps my brain cells alive.

The best things in life are not always free.

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