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#1 2024-09-23 03:27:17

Oculus8596
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From: Great Lakes,Illinois
Registered: 2024-09-18
Posts: 126

Find x

If (x^²)^²= 16, what is the value of x?

Well, (x^2)^2 becomes x^4.

x^4 = 16

Take fourth root on both sides of the equation.

4root{x^4} = 4throot{16}

x = 2, x = -2

There are two values of x because I had to take the fourth root. If the fourth root was the given problem, then x = 2.

Is this a good explanation?

Last edited by Oculus8596 (2024-09-23 03:29:07)


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#2 2024-09-23 03:52:25

Bob
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Registered: 2010-06-20
Posts: 10,597

Re: Find x

Yes, good.  If you ever get to complex numbers you will discover there are also 2 complex values that work.

Bob


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Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-09-23 03:57:16

Oculus8596
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From: Great Lakes,Illinois
Registered: 2024-09-18
Posts: 126

Re: Find x

Bob wrote:

Yes, good.  If you ever get to complex numbers you will discover there are also 2 complex values that work.

Bob

I will post complex numbers in due time. Math is the only subject that keeps my brain cells alive.


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